If 9/5 of a number exceeds 5/7 of that number by 70 , find that number.
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7 of that number by 70 , find that number.
If 9/5 of a number exceeds 5/7 of that number by 70 , find that number.
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Verified answer
let the number be x.
given that 9/5 of a number exceeds 5/7 of that number by 70.
Therefore,
9x/5 = 5x/7 + 70
= 9x/5 - 5x/7 = 70
= 63x-25x/35 = 70
= 38x = 2450
x = 64.47
Hence, the required number is 64.47.
Answer:
The required number is 64(approximately)
Step-by-step explanation:
Solving an equation:
Let x be the required number.
Given condition is
9/5 of a number exceed 5/7 of that number by 70.
x(9/5) = x(5/7)+70
(9x/5)-(5x/7) = 70
(63x-25x)/35 = 70
38x/35 = 70
x = (35×70)/38
x = (35×35)/19
x = 1225/19
x = 64.47
x = 64 (approximately)
Hence, the required number is 64.
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