7. Replace * by the smallest digit so that the number formed is divisible by 9.
(a) 6*5
(b) 21*2.
Ilsing the digits 1 and 5 form the smallest three-digit number which are divisible by ea
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7. Replace * by the smallest digit so that the number formed is divisible by 9.
(a) 6*5
(b) 21*2.
Ilsing the digits 1 and 5 form the smallest three-digit number which are divisible by ea
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Step-by-step explanation:
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(a)
The number is given as _6724.
The number is divisible by 3 if the sum of its digits is divisible by 3.
Adding the digits of the given number,
6+7+2+4=19
If 2 is added to the above number then the number will become 21 which is divisible by 3 and also, 2 is the smallest number that can fill the missing space.
Now, if 8 is added to the given number then the number will become 27 which is divisible by 3 and 8 is largest number that can make the given number divisible by 3.
Therefore, the smallest number will be 2 which will form 26724 and the largest number will be 8 forming 86724.
(b)
The number is given as 4765_2.
The number is divisible by 3 if the sum of its digits is divisible by 3.
Adding the digits of the given number,
4+7+6+5+2=24
If 0 is added to the above number then the number will become 24 which is divisible by 3 and also, 0 is the smallest number that can fill the missing space.
Now, if 9 is added to the given number then the number will become 33 which is divisible by 3 and 9 is largest number that can make the given number divisible by 3.
Therefore, the smallest number will be 0 which will form 476502 and the largest number will be 9 forming 476592.
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