Solve x=log (1/8) by rewriting in exponential form
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Solve x=log (1/8) by rewriting in exponential form
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Answer:
Use the definition of a logarithm
[tex] \rm{{log}_{b} (x) = y} [/tex]
[tex] \rm{{b}^{y} = x} [/tex], to convert from the logarithm form to the exponential form.
[tex] \rm{{10}^{x} = \dfrac{1}{8}} [/tex]
Step-by-step explanation:
Step 1:
For logarithm equations,
[tex] \rm{{log}_{b} (x) = y} [/tex] is equivalent to [tex] \rm{{b}^{y} = x} [/tex] such that x > 0, b > 0, and b ≠ 1. In this case, b = 10, x = 1/8 and y = x.
Step 2:
Substitute the value of b, x and y into the equation [tex] \rm{{b}^{y} = x.}[/tex]
[tex] \bf{{10}^{x} = \dfrac{1}{8}} [/tex]
[tex] \rule{180pt}{3pt} [/tex]