8. Find the least number which when
divided by 60, 120 and 180 leaves a
remainder 5 in each case.
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8. Find the least number which when
divided by 60, 120 and 180 leaves a
remainder 5 in each case.
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To find that least numberw hich divide by 60, 120and 180 leave a reminder 5.
In ,case we have to find the l.c.m of the given numbers
and then add five in that number
60 = 2×2×3×5
120 =2×2×2×3×5
180 =2×2×3×3×5
l.c.m =360
Now, add 5
so, 5 + 360 = 365
Hence, 365 is the least number which is divide by 60,120and 180 leaves reminder 5
Answer:
∴lcmof60120and180is
60 = 2×2×3×5
120 =2×2×2×3×5
180 =2×2×3×3×5
l.c.m =360
Now, add 5
so, 5 + 360 = 365
Hence, 365 is the least number which is divide by 60,120and 180 leaves reminder 5
chec