A light string passing over a smooth light pulley connect two blocks of masses mm₁ and m₂ (vertical) . if the acceleration of the system is g/8 , then the ratio of the masses is [AIEEE 2002]
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A light string passing over a smooth light pulley connect two blocks of masses mm₁ and m₂ (vertical) . if the acceleration of the system is g/8 , then the ratio of the masses is [AIEEE 2002]
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Explanation:
Let mass of two blocks be a and b respectively and their common acceleration be acc.
Applying equation of motion, assuming b>a
bg−T=b×acc
T−ag=a×acc
Substituting value of acc as g/8 and eliminating T,
we get b:a=9:7
Explanation:- As the string is inextensible , both masses have the same acceleration a . Also , the pulley is massless and frictionless , hence the tension at both ends of the string is the same suppose , the mass m₂ is greater than mass m₁ , so the heavier mass m₂ is accelerating downward and the lighter mass m₁ is accelerating upwards.
Therefore , by Newton's 2nd law
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