In ∆ABE, sin 60°=AE/AB √3/2=AE/16
=>AE=8√3 cm
and cot 60°=BE/AE
1/√3=BE/8√3
=>BE= 8 cm
EC=BC - BE
=23-8=15 cm
in rt ∆ AEC,
by Pythagoras theorem,
AC sq. = AE sq.+EC sq.
=(8√3) sq. + 15 sq.
=192+225
417
=>AC=√417
=20.42
.. now I am noticing.. question explain karte karte answer nikal diye
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