(8abc − 16ab) ÷ (−8ab) =
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Answer:
[tex] \frac{8abc - 16ab}{ - 8ab} \\ \\ = \frac{8ab(c - 2)}{ - 8ab} \\ \\ = - (c - 2) \\ \\ [/tex]
Answer:
We get the Final answer is [tex](8abc-16ab)[/tex] ÷ [tex](-8ab)[/tex][tex]=-(c-2)[/tex]
Step-by-step explanation:
This is the division sum.
That is, [tex](8abc-16ab)[/tex] ÷ [tex](-8ab)[/tex] [tex]=\frac{8abc-16ab}{(-8ab)}[/tex]
here we should take the common value in the numerator. In the numerator, [tex]ab[/tex] is the common term and numerical value [tex]8[/tex] also a common value.So that,
[tex]\frac{8abc-16ab}{(-8ab)}=\frac{8ab(c-2)}{(-8ab)}[/tex]
Now cancel [tex]8ab[/tex] in the numerator and denominator. Then we get te following equation.
[tex]\frac{8ab(c-2)}{(-8ab)}=\frac{c-2}{(-1)}[/tex]
It can be written as, [tex]\frac{8ab(c-2)}{(-8ab)}=-(c-2)[/tex]