8xsqare+18x+7=0
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Step-by-step explanation:
8x²+18x+7=0
8x²+4x+14x+7=0
4x(2x+1)+7(2x+1)=0
(4x+7)(2x+1)=0
[tex]by \: factorization \\ 8x {}^{2} + 18x + 7 = 0 \\ 8x {}^{2} + 14x + 4x + 7 = 0\\ 2x < 4x + 7 > + 1 < 4x + 7 > = 0\\ < 4x + 7 > \: \: \: < 2x + 1 > = 0 \\ 4x + 7 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x + 1 = 0 \\ 4x = - 7 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x = - 1 \\ x = \frac{ - 7}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{ - 1}{2} [/tex]