9. The base of a parallelogram is twice its height. If the area of the parallelogram is 512 cm
find the base and the height,
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9. The base of a parallelogram is twice its height. If the area of the parallelogram is 512 cm
find the base and the height,
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Solution!!
The base is twice the height of the parallelogram. The area of the parallelogram is given. We have to find the base and height.
Area = 512 cm² (Area is always in square units)
Let the height be h
Let the height be hBase = 2 × h = 2h
Area of the parallelogram = Base × Height
512 cm² = 2h × h
512 cm² = 2h²
512/2 cm² = h²
256 cm² = h²
√256 cm² = h
h = 16 cm
We know the height of the parallelogram. We can easily find the base now.
Base = 2h
Base = 2 × 16 cm
Base = 32 cm
[tex] \underbrace \text{Answer:}[/tex]
❃Formula used:
❃Solution:
Given,
Area= 513cm²
Let the height be "x" and the base be "2x".
According to the condition:
[tex] = > \bold{512=2x \times x}[/tex]
[tex] = > \bold{512 = {2x}^{2} }[/tex]
[tex] = > \bold{ \frac{512}{2} = {x}^{2} }[/tex]
[tex] = > \bold{256 = {x}^{2} }[/tex]
[tex] = > \bold{x = \sqrt{256} }[/tex]
[tex] = > \bold{x = 16cm}[/tex]
Therefore,
Thus, The base is 32cm and the height is 16cm.