9. The base of a triangular field is three times its altitude. If the cost of levelling the field at 30.50 per sq.
metre is 7350, find its base and height
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9. The base of a triangular field is three times its altitude. If the cost of levelling the field at 30.50 per sq.
metre is 7350, find its base and height
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We know the area of a triangle = \frac{1}{2} x (base) x (altitude)
Let the altitude of the triangle = a
therefore, base length = 3a
=> area, A = \frac{1}{2} x 3a x a
=> A = \frac{3}{2} a^{2} sq.metre
Price of levelling the field of area A = A x 30.50
Given : 30.50 A = 7350
=> A = 240.98 sq.metre
Therefore, \frac{3}{2} a^{2} = 240.98
=> a = 12.67 metre
Hence, altitude length = 12.67 metre , and base length = 38.01 metre
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