Solve for ' x ' = √a/b=[b/a]^-3x
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a]^-3x
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Answer:
[tex]\huge{\mathbb{ANSWER : -}}[/tex]
given root under a/b =(b/a)^1-3x
As (a/b)^1/2=(b/a)^1-3x
Then (b/a)^-1/2 =(b/a)^1-3x
Then solve for x in
-1/2=1-3x
You get x =1/2
Answer:
Here, (a/b)^1/2=(b/a)^(1-3x)
=> (b/a)^-1/2=(b/a)^(1-3x)
=> 1-3x = -1/2
=> 3x = 1+1/2
=> 3x = 3/2
=> x =3/2×1/3
=> x = 1/2
hence, x = 1/2 answer.