A 500g stone is thrown up with velocity of 15ms^-1. Find its
i) P.E at maximum height
ii) K.E at its hit the ground
plz answer me.
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A 500g stone is thrown up with velocity of 15ms^-1. Find its
i) P.E at maximum height
ii) K.E at its hit the ground
plz answer me.
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Answer:
Explanation:
Kinetic Energy, K.E=0.5×m×v
2
K.E=0.5×0.5×15×15=56.25J
It has 56.25 J at initial point as total energy.
Total energy=P.E.+K.E.
56.25=P.E.+K.E.
As energy is conserved total energy after reaching ground also must be 56.25 J at which P.E. has a value of zero because of zero height.
Hence K.E=56.25J.
K.E at it's hit the ground ii option