A 6cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 30 cm the distance of the object from the mirror is 45 CM use mirror formula to determine the position nature and size of the image formed
Share
A 6cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 30 cm the distance of the object from the mirror is 45 CM use mirror formula to determine the position nature and size of the image formed
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
1/f = 1/v + 1/u
f= -30cm
u= -45cm
1/v = 1/f-1/u == -1/30+1/45 = -1/90
Therefore , V = -90cm
Real image
Size == hi/ho = -v/u == hi = -12cm
Height of image = 12cm below the principal axis
Answer:
The distance of the image is 90 cm, size of the image is 12 cm and enlarged.
Explanation:
h = 6cm
f = -30cm
u = -45
1/f = 1/v + 1/u
1/v = 1/f - 1/u
1/v = 1/ ( -30) - 1/ (-45)
1/v = 1/-90
v = -90cm from the pole of the mirror
v = -90cm from the pole of the mirrorSize of the image
m = -v /u
= -90/45
= -2
ux ☞ m = h'/h = h'
= -2×6 = -12 cm
hope it's helpful to you ✨ mark as brainlist pls ✨