a) An object moves 18 m in the first
3 s, 22 m in the next 3 s and 14 m in
the last 3 s. What is its average
speed?
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a) An object moves 18 m in the first
3 s, 22 m in the next 3 s and 14 m in
the last 3 s. What is its average
speed?
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Answer:
24kmph
Explanation:
Now in this case there is two motion .
In first case distance covered =18m.
In second case distance covered =22m.
So➡ total distance covered =40m.
In first case time taken =3secs.
In second case time taken =3secs.
So➡ total time taken =6secs.
So :- Averagespeed=totaldistancecovered/totaltimetaken.
Averagespeed=40m/6secs.
⛧ Averagespeed=6.667m/s. ⛧
Which is also equal to⛧ 24km/hr. ⛧
Thanks.