A bag contains ₹ 102 in the form of rupee 50 paisa and 10 paisa coins in the ratio 3 : 4 : 10 . The number of 10 paisa coins is.
With correct solution.
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A bag contains ₹ 102 in the form of rupee 50 paisa and 10 paisa coins in the ratio 3 : 4 : 10 . The number of 10 paisa coins is.
With correct solution.
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Answer:
The number of 10 paisa coins is 170
(₹ 17)
Step-by-step explanation:
Let,
1 Rupee coins = 3x
50 paisa coins = 4x
10 paisa coins = 10x
Total amount in bag = ₹ 102
1 rupee = 100 paisa
So,
₹ 102 × 100
10,200 paisa
⇒ 3x × 100 = 300x
⇒ 4x × 50 = 200x
⇒ 10x × 10 = 100x
★ According to the question :
⇒ 300x + 200x + 100x = 10,200
⇒ 600x = 10,200
⇒ x = 10,200 / 600
⇒ x = 17
____________________________
★ Value of 3x :
⇒ 3 (17)
⇒ 51
1 Rupee coins = 51 coins
____________________________
★ Value of 4x :
⇒ 4 (17)
⇒ 68
50 paisa coins = 68 coins
____________________________
★ Value of 10x :
⇒ 10 (17)
⇒ 170
10 paisa coins = 170 coins
Therefore,
The number of 10 paisa coins is 170
(₹ 17)
Verified answer
Answer:
1 (3x) +50/100 (4x )+ 10/100 (10x) =102 =3x+1/2 (4x)+1/10 (10x)=102 3x+2x+x=102 6x=102 x =102/6=17 10x=17×10=170. Number of 10 paise coin is 170. That set.