A ball is thrown upwards with a velocity 20 ms from the top of tower having a height 50 m. whai is time elasped when it passes again edge of tower
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A ball is thrown upwards with a velocity 20 ms from the top of tower having a height 50 m. whai is time elasped when it passes again edge of tower
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Answer:
bro my answer is correct
that is 4 seconds
see , velocity is given as 20 m/s
g = -10 m/s2
put these values in v=u+ at
v=0
a=-g=10
0=20-10t
-20=-10t
t=2s
2 seconds will be consumed in going up by the ball and 2 seconds will be consumed by coming down by the ball so the ball will cross the edge after 4 seconds
answer =2+2 = 4 seconds
plz mark as brainliest