A ball of mass 200 g falls from a height of 2 m . What is the kinetic energy during the ball when it reaches the ground.
A ball of mass 200 g falls from a height of 2 m . What is the kinetic energy during the ball when it reaches the ground.
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Answer:
Explanation:
Solution :-
Given :-
Mass of the ball, m = 200 g = 200 × 10⁻³ kg
Height or Distance, d = 2.0 m
Acceleration due to gravity, g = 9.8 m/s²
To Calculate :-
K.E of the ball when it reaches the ground = ??
Formula to be used :-
P.E at the top = P.E at the ground
P.E = mgh
P.E = 200 × 10⁻³ × 9.8 × 2.0
P.E = 3.92 J
K.E of the ball when it reaches the ground its same as P.E at the top.
K.E = 3.92 J
Hence, the K.E of the ball when it reaches the ground is 3.92 J.
Verified answer
Loss in potential energy = gain in kinetic energym = 0.2 Kg.
g = 10 m/sec²
h = 2 m
loss in potential energy = mgh = 0.2*10*2 = 4 joule
hence kinetic energy of the ball when it reaches the ground = 4 joule