.A ball of mass 5 kg is moving with velocity 4ms-1 in and comes to rest after travelling a distance of 4m. The force exerted on an object is pla ans fast mak barinliest
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.A ball of mass 5 kg is moving with velocity 4ms-1 in and comes to rest after travelling a distance of 4m. The force exerted on an object is pla ans fast mak barinliest
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Answer:
Step-by-step explanation:
Let their velocities after the collision be v 1 and v 2
As we know for elastic collision.
Relative velocity of approach = relative velocity of separation
10−4=v 2 −v 1
⇒6=v 2 −v 1
⇒v 1 =v 2 −6
Applying conservation of momentum,
10×10+5×4=10v 1 +5v 2
120=10v 1+5v 2
120=10(v 2−6)+5v 2 =15v 2 −60
15v 2 =180⇒v2 =12cm/sec
v 1 =6cm/sec