A baseball is popped straight up into the air and has a hang-time of 6 s. Determine the maximum height to which the ball rises.
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A baseball is popped straight up into the air and has a hang-time of 6 s. Determine the maximum height to which the ball rises.
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The correct option is C
45 m
Time taken to reach the maximum height =
6
2
= 3 s
Final velocity, v = 0
Using first equation of motion, v = u + at
0 = u - 10
×
3
u = 30 m/s
Now,
s = ut +
1
2
a
t
2
s= 30
×
3 –
1
2
×
10
×
3
×
3
Hence, s = 90 – 45 = 45 m
Answer:
9
Explanation:
m= 6
v= 4
mgh= 10
6×4×10 = 420