a bicnvex lens of radii 5 cm of 5 diopter power then what is the refractive index of the lens
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a bicnvex lens of radii 5 cm of 5 diopter power then what is the refractive index of the lens
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Answer:
Power lens,
P (in dioptre) = 100 / focal length f (in cm)
Therefore , f = 100 / 5 = 20 cm
So , the solution will be
According to lens maker's formula,
1/f = (μ - 1) [ (1/R₁) - (1/R₂) ]
For biconvex lens, R₁ = +R , R₂ = R
1/f = (μ - 1) [ (1/R) + (1/R) ]
1/f = (μ - 1) [ (2/R) ]
1/5 = (μ - 1) [ (2/5) ]
(μ - 1) = 1/2
μ = 1/2 + 1
μ = 3/2
The refractive index of the lens is 3/2
Answer:
Power lens,
P (in dioptre) = 100 / focal length f (in cm)
Therefore , f = 100 / 5 = 20 cm
So , the solution will be
According to lens maker's formula,
1/f = (μ - 1) [ (1/R₁) - (1/R₂) ]
For biconvex lens, R₁ = +R , R₂ = R
1/f = (μ - 1) [ (1/R) + (1/R) ]
1/f = (μ - 1) [ (2/R) ]
1/5 = (μ - 1) [ (2/5) ]
(μ - 1) = 1/2
μ = 1/2 + 1
μ = 3/2
The refractive index of the lens is 3/2
Explanation:
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