a big dug ate 64 small bugs in 4 day. each day it ate 6 more bugs than it ate on the previous day. how may small bugs did the big dug eat on, the first day and the third day
a big dug ate 64 small bugs in 4 day. each day it ate 6 more bugs than it ate on the previous day. how may small bugs did the big dug eat on, the first day and the third day
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then no. of bugs are in second day=x+6
no. of bugs at
e in this day=x+12
no. of bugs ate in fourth day=x+18
According to question equation will be
x+x+6+x+12+x+18=64
4x+36=64
4x=64-36=28
4x=28
x=28/4=7
Bugs ate on first day=x=7
Bugs ate on third day=x+18=7+18=25