A block of mass 5 kg is initially lying at rest on a smooth floor. My friend exerts a constant force of 50 N on it. If I exert a force of T on the block, opposing my friend’s force, the block has an acceleration of magnitude aa. If I double my force to 2T, the magnitude of block’s acceleration remains the same. Find the magnitude of the acceleration of the block when I triple my force to 3T.
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Explanation:
Using work-energy theorem:
W.D
force
+W.D
friction
=ΔK.E
45×2−25×2=KE
final
KE
final
=40 J
solution