a body Falls 8 metre in the first second of its motion 24 m in the second second 40 metre in the third and so on how long will it take to fall 2048 Metre?
a body Falls 8 metre in the first second of its motion 24 m in the second second 40 metre in the third and so on how long will it take to fall 2048 Metre?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
now applying second law of motion, we get
2048= (0) t + 1/2(16) t^2
t^2 = 256
t= 16 sec
Answer:
The AP is 8, 24, 40,..., and the sum is 2048.
We have to determine n.
Here a = 8, d = 16
Since, Sn = 2048, we have
2048 = begin mathsize 12px style straight n over 2 end style [2 x 8+(n - 1)16]
2048 = n [8 + 8n - 8]
2048 = 8n2
n2 = 256 i.e. n = 16
(as n being number of terms, it can't be negative)
Hence, the body will take 16 seconds to fall 2048 metres.
hope it helps
tq............///////////
Step-by-step explanation: