A body of mass 20kg is kept at a height of 15m. Calculate the potential energy of the body.
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A body of mass 20kg is kept at a height of 15m. Calculate the potential energy of the body.
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Explanation:
↪Given:
Mass of object is 20 kg.
Height = 15 m
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\bf \huge \hookrightarrow \: \: To \: \: Find :↪ToFind:
We have to find the potential energy of the body.
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\bf \Large \hookrightarrow \: \: Formula \: \: Using :↪FormulaUsing:
\Large \mid \underline {\mathcal {{{\color{red}{\bf \Large \rightarrow \: \: P. E \: = \: mgh }}}}} \mid∣
→P.E=mgh
∣
P.E denotes Potential Energy.
m denotes mass
g denotes Acceleration due to gravity.
h denotes height.
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\begin{gathered}\large{\textrm{{{\color{navy}{ \: value \: of \: m \: = \: 20 \: kg}}}}} \\ \\ \large{\textrm{{{\color{navy}{value \: of \: h \: = \: 15 \: m}}}}} \\ \\ \large{\textrm{{{\color{navy}{value \: of \: g \: \: \: = \: 10 \: m/s² }}}}}\end{gathered}
value of m = 20 kg
value of h = 15 m
value of g = 10 m/s²
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☛ Now ,
\large \mid \underline {\mathcal {{{\color{purple}{\bf \Large \rightarrow \: \: P. E \: = \: mgh }}}}} \mid∣
→P.E=mgh
∣
\large \underline {\mathcal {{{\color{purple}{\bf \Large \rightarrow \: \: P. E \: = \: 20 \: \times 10 \: \times 15 }}}}}
→P.E=20×10×15
\large \mid \underline {\mathcal {{{\color{purple}{\bf \Large \rightarrow \: \: P. E \: = \: 3000 }}}}} \mid∣
→P.E=3000
∣
Hence , the potential energy of body is 3000J.