A body of mass 2kg and density 8000kg per metre cube is completely dipped in a liquid of density 800kg per metre cube. Find the force of buoyancy on it.
A body of mass 2kg and density 8000kg per metre cube is completely dipped in a liquid of density 800kg per metre cube. Find the force of buoyancy on it.
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Verified answer
The buoyancy force exerted by a liquid on an object dipped in it will beF = ρgV
where ρ is the density of the liquid, V is th volume of the object immersed in the liquid and g is the acceleration due to gravity.
So
here
ρ = 800 kg/m3
g =10 m/s2
and V = mass/density = 2/8000 = 2.5 X 10-4 m3
thus,
F = 800 X 10 X 2.5 X 10-4 = 8 X 2.5 X 10-1
or
F = 2 N
Verified answer
Heya user !!Here's the answer you are looking for
☛Buoyant force = Upthrust = mass of liquid displaced.
Now, we know,
So,
☛ Mass of liquid displaced = Volume of liquid displaced × density of the liquid
By Archimedes principle, we know that when an object is partially or completely immersed in a liquid then the volume of liquid displaced is equal to the volume of immersed part of the object.
So,
☛ Volume of liquid displaced = Volume of the body
➡️Mass of body = 2kg
and it's density = 8000kg/m³
Thus, mass of water displaced
= volume of liquid displaced × density of liquid
Therefore, the upthrust or buoyant force
➡️ Therefore, the force is 1.96N
★★ HOPE THAT HELPS ☺️ ★★