A body of mass 3 kg is dropped from the height of 15 m. Find the kinetic energy of the body when it is at a height of 10 m, above the ground.
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A body of mass 3 kg is dropped from the height of 15 m. Find the kinetic energy of the body when it is at a height of 10 m, above the ground.
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Answer:
The time at which body touches ground is t=
2d/g = (2∗500)/10 =10s
Therefore v=gt=10∗3=30m/s
Therefore KE= 21
∗m∗v 2 = 21
∗3kg∗302
=1350J