a body starting from rest moving with a constant acceleration covers 15m in 3sec. find the distance covered by it in 12sec
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a body starting from rest moving with a constant acceleration covers 15m in 3sec. find the distance covered by it in 12sec
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Answer:
Given:-
Initial velocity ,u = 0m/s
Distance covered ,s = 15m
Time taken ,t = 3 s
To Find:-
Distance covered by it in 12 seconds
Solution:-
Using 2nd equation of motion
s = ut + ½at²
15 = 0×3 + ½×a × 3²
15 = 0 + 1/2 × a × 9
15×2 = 9 × a
30 = 9× a
a = 30/9
a = 10/3 m/s²
Now, calculating the distance covered by body in 12 second
s = ut + 1/2 at²
s = 0 × 12 + 1/2 × 10/3 × 12²
s = 0 + 5/3 × 144
s = 5 × 48
s = 240 m
The distance covered by the body in 12 seconds is 240 metres
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Given:-
Initial velocity ,u = 0m/s
Distance covered ,s = 15m
Time taken ,t = 3 s
To Find:-
Distance covered by it in 12 second.
Solution:-
It is given that the body starts from rest and moving with a constant acceleration . We have to calculate the distance covered by it in 12 second . Firstly we calculate the acceleration of the body . Using 2nd equation of motion
s = ut + 1/2at²
where,
s denote distance covered
u denote initial velocity
t denote time taken
a denote acceleration
Substitute the value we get
15 = 0×3 + 1/2×a × 3²
15 = 0 + 1/2 × a × 9
15×2 = 9 × a
30 = 9× a
a = 30/9
a = 10/3 m/s² = 3.33 m/s²
Now, calculating the distance covered by body in 12 second . Again using 2nd equation of motion
s = ut + 1/2 at²
substitute the value we get
s = 0 × 12 + 1/2 × 10/3 × 12²
s = 0 + 5/3 × 144
s = 5 × 48
s = 240 m
Hence the distance covered by the body in 12 second is 240 metres
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