A box wheighs 16 N. Its base has an area of 6 m square. What pressure does it exert? Another identical box is placed on top of the first box what is the pressure now?
A box wheighs 16 N. Its base has an area of 6 m square. What pressure does it exert? Another identical box is placed on top of the first box what is the pressure now?
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Answer:
R.E.F image
The FBD for the box of mass m when put on the table is,
The normal force N
1
is equal to the weight of the box.
N
1
=mg
The FBD of the first box when an identical box of mass m is placed above it is,
The normal force N
2
is equal to the weight of the second box.
N
2
=mg
The normal force N
3
is equal to the combined weight of the boxes.
N
3
=2mg
Clearly, N
1
=N
2
<N
3
Hence, option C is correct.
Explanation:
Pressure= force/area
= 16/6
= 2.67 Pascals
pressure of identical box above
2.67+2.67
= 5.34 Pascals
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