a boy runs around the boundary of a square field of side 6 m in 10 seconds the displacement of the boy in one minute is
urgent pls tell fast
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a boy runs around the boundary of a square field of side 6 m in 10 seconds the displacement of the boy in one minute is
urgent pls tell fast
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Answer:
360m
Explanation:
a boy runs around the boundary of a square field of side 6 m in 10 seconds the displacement of the boy in one minute is
a boy run in 10 seconds =6m
a boy run in one minute =
1 minute = 60 Seconds
so, 6*60 =360 m
Verified answer
Answer:
Explanation:
displacement = h^2= p^2+b^2
h^2 = 6^2+ 6^2
H^2 = 36+36
H^2= 72
H^2 = 2 Root 6
displacement = 2 root 6
time = 10 s
1s = 1/60 minutes
= 0.7 minutes
displacement in time = 0.7 * 10
7/10*10 = 7 m
ans = 7m