A boy throws a ball vertically up . it returns to the ground after 5 seconds . Find
i. The maximum height reached by the ball.
ii. The velocity with which the ball is thrown up.
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A boy throws a ball vertically up . it returns to the ground after 5 seconds . Find
i. The maximum height reached by the ball.
ii. The velocity with which the ball is thrown up.
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Answer:
Explanation:
Given :-
Time = 5sec
V = 0 (in going up)
U = 0 (in comming down)
Find :-
H and U by which it is thrown up
Since the total time is 5 sec ,therefore half time will be taken to go up and another half will be taken to go down .
We know that ,
V = U + gt
0 = U - 10*2.5
U = 25 m/sec
Also,
V² = U² +2gs
0 = 625 - 20s
s = 625/20 = 31.25 m