A bulb of 60 watt was connected to a line of 240 volt suddenly the voltage drops to 120 Volt what will be the power and current of the bulb
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A bulb of 60 watt was connected to a line of 240 volt suddenly the voltage drops to 120 Volt what will be the power and current of the bulb
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Explanation:
Power rating of the bulb = 60W
Voltage rating of the bulb = 220V
The resistance of the bulb can be calculated by the heating effect formula:
P = V^2/R
R = (220*220)/60 ohms
Now when the voltage drops to 192 V, R will remain constant as it's a material property;
According to Ohm's law:
I = V/R
I = 192/[(220*220)/60] = 0.238 A
P = V*I
P = 192*192/[(220*220)/60]= 45.699 W
hopefully its helped u dear :)