A can done a work in 12days and B is 60% more efficiency than A ,
how much time will take to complete the work where A ,B work together
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A can done a work in 12days and B is 60% more efficiency than A ,
how much time will take to complete the work where A ,B work together
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Answer:
please mark as brainliast
Step-by-step explanation:
Since B's efficiency is relative to A , consider B's no. of days to be "x"
1 day work of B = 1/x , 1 day work of A = 1/12
So, according to the question, The efficiency of B is =>
( ( (1/x)-(1/12) )/ (1/12) ) * 100 = 60 (Since B is 60% more efficient than A)
This would become => ( (12-x)/x)=0.6 => 1.6x = 12 => x= 7.5 days