A car accelerates from rest at a constant rate a for some time, after which it decelerates at a constant rate B and comes to rest. If
the total time elapsed is t, then the displacement of the car is
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A car accelerates from rest at a constant rate a for some time, after which it decelerates at a constant rate B and comes to rest. If
the total time elapsed is t, then the displacement of the car is
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Answer:let max velocity be v
therefore v=0+at1---------1
also 0=v-bt2---------2
from above we get,
t1=v/a and t2=v/b
t1+t2=t=v/a+v/b
therefore v=(ab/a+b)t