A car can finish a certain January in 10 hours at a speed of 48 km per hour.By how much should its speed be increased so that it may take only 8 hours to cover the same distance.
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A car can finish a certain January in 10 hours at a speed of 48 km per hour.By how much should its speed be increased so that it may take only 8 hours to cover the same distance.
fast it's urgent
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to cover 480 km in 8 hrs the speed should be 480/8=60kmph
d = s×t
= 48×10
=480
if it take only 8 hours
s = d/t
=480÷8
= 60 kmph
speed should be increased so that it take only 8 hours to cover the same distance = 60-48=12 kmph
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