A car is travelling along the road at 8m s-¹.It accelerates at 1 ms-² for a distance of 18m.How fast is it then travelling?
A car is travelling along the road at 8m s-¹.It accelerates at 1 ms-² for a distance of 18m.How fast is it then travelling?
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Initial speed u=8 m/s
Initial speed u=8 m/s Acceleration a=1 m/s
Initial speed u=8 m/s Acceleration a=1 m/s 2
Initial speed u=8 m/s Acceleration a=1 m/s 2
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 m
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aS
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8 2
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8 2 =2×1×18
Initial speed u=8 m/s Acceleration a=1 m/s 2 Distance S=18 mUsing v 2 −u 2 =2aSOr v 2 −8 2 =2×1×18⟹ v=10 m/s
hope it helps you
ANSWERS:
Initial speed u=8 m/s
Distance S=18 m
⟹ v=10 m/s