a car moving on a road with a uniform acceleration covers 20m in the first second and 40m in next second what is the acceleration! please answer me with full explanation
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a car moving on a road with a uniform acceleration covers 20m in the first second and 40m in next second what is the acceleration! please answer me with full explanation
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Answer:
distance travelled in 1st second=20m
time taken to travel this distance=1s
So speed in first second is dist/time = 20m/s
Similarly speed in 2nd second is 40m/s
Now acceleration = dv/dt
Here dv means change in v, where v is velocity and dt means change in t where t is time interval.
Change in velocity = final vel. — initial vel.
That is, 40-20 = 20m/s
And change in time = 2 — 1 = 1s
So acceleration is 20m/s / 1s = 20m/s^2 Ans.
Metre per second square is the standard unit of acceleration.
Explanation:
Answer:
Let the initial velocity be u and acceleration be a.
Case 1 :
Distance covered S=20 m
Time taken t=1 s
Using S=ut+
2
1
at
2
Or 20=u(1)+
2
1
a(1)
2
⟹ 20=u+
2
a
We get u=20−
2
a
Case 2 :
Total distance covered S=20+30=50 m
Total time taken t=1+1=2s
So, 50=u(2)+
2
1
a(2)
2
or 50=2u+2a
Or 50=2(20−
2
a
)+2a
Or 50=40−a+2a
⟹ a=10 m/s
2
Explanation:
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