A car starts from rest and moves with constant acceleration the ratio of distance covered in 3rd second to that covered in three second is
A car starts from rest and moves with constant acceleration the ratio of distance covered in 3rd second to that covered in three second is
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5 : 18
Explanation:
Distance Covered in 3rd second will be the difference of (distance Covered in 3 seconds) and (distance Covered in 2 seconds).
So,
Distance Covered in 3 seconds =
s = ut + 1/2 at²
s = 0×t + 1/2 a 3² (Starts from rest u=0)
s = 9/2 a __(1)
and
Distance Covered in 2 seconds =
s = ut + 1/2 at²
s = 0×t + 1/2 a 2² (Starts from rest u=0)
s = 4/2 a = 2a __(2)
Now,
Distance Covered in 3rd second =
(1) - (2)
9/2 a - 2a
5/4 a __(3)
Ratio =
(3) : (1)
5/4 a : 9/2 a
5 : 18
Hope It Helps ;)