a cell supplies a current of 2A when it is connected to a 5 ohms resistance and supplies a current of 1.2 A, if it is connected to a resistance 9 ohms. find the e.m.f. and internal resistance of the cell.
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a cell supplies a current of 2A when it is connected to a 5 ohms resistance and supplies a current of 1.2 A, if it is connected to a resistance 9 ohms. find the e.m.f. and internal resistance of the cell.
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Given,
I=>2A
R=> 5ohm
emf (V) => 2×5. {By ohms law ,V=> IR}
Emf (V) => 10 V
Supplied emf (E) => ?
E=> IR
E=> 1.2 ×9
E => 10.8 V
Formula:-
Internal resistance (r) => (E-V/V)R
r =>(10.8-10/10)5
r => 0.4 ohm.
Hope this helps you a little!!!
Answer:
e.m.f=12v, internal resistance =1Ω