A charge of 6.4 C is transferred through the filament
of an electric bulb in 20 seconds. How many electrons are transferred ? How many protons are transferred ?
What will be the reading of an ammeter connected in series with the bulb ?
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A charge of 6.4 C is transferred through the filament
of an electric bulb in 20 seconds. How many electrons are transferred ? How many protons are transferred ?
What will be the reading of an ammeter connected in series with the bulb ?
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Answer:
10^20
Explanation:
Charge = Current × time, that is,Q=it where,
charge is Q,it is measured in colombus(C)
current is I, it is measured in amperes(A)
time is t, it is measured in seconds (S)
The relationship between electronic charge, charge and number of electrons are Protons is given as follows.
charge = number of electrons or Protons x electronic charge, that is Q= ne where, charge is Q, it is measured in colombus(C) number of electrons/protons is n, it is measured in numbers
electronic charge is e, It has a standard value = 1.6 × 10^-19. colombus (C)
Equating both the above equations, that is,
It = ne we get, n = (I × T) / e = (1 × 16) / (1.6 × 10^-19) = 10^20.
Hence, number of electrons passing through a cross section of the filament in 60 seconds would be roughly 10^20