A chord of length 8cm is drawn at a distance of 4cm from the centre of curvature of the circle . Find the radius of circle
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A chord of length 8cm is drawn at a distance of 4cm from the centre of curvature of the circle . Find the radius of circle
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Our problem:-
A chord of length 8 cm is drawn at a distance of 4 cm from the center of the curvature of the circle.
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The figure consists of:-
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To find:-
The radius, [tex]\rm r[/tex]
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[tex]\Large\textrm{Explanation}[/tex]
The chord forms a right angle with the radius.
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By the Pythagorean theorem,
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[tex]\small{\Longrightarrow\boxed{\rm r^{2}=(Half\ of\ the\ chord)^{2}+(Distance\ from\ the\ center)^{2}}}[/tex]
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So,
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[tex]\rm\Longrightarrow r^{2}=4^{2}+4^{2}[/tex]
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[tex]\rm\Longrightarrow r^{2}=32[/tex]
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[tex]\rm\Longrightarrow r=4\sqrt{2}[/tex]
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[tex]\textbf{$\Longrightarrow$ The radius is $\bf 4\sqrt{2}$ cm.}[/tex]
QUESTION:-
GIVEN:-
TO FIND :-
SOLUTION :-
first we have formula :-
r = ( half of the chord ) + ( distance from the centre)
then, we will add 4 with 4
we get :-
= 4 + 4
then, we will multiply 4 with 8
we get :-
= 32
so, we get radius
radius = 4√2
radius of circle = 4√2