A conc. HCL contains 38% HCL by mass. calculate molarity of the solution if the density =1.10g/L.?
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Take 1.0L of this solution .
Mass of this solution = 1100g
38% HCl = 38/100*1100 = 418g HCl
Molar mass HCl = 36.5g/mol
Mol HCl in 418g = 418/36.5 = 11.45 mol HCl dissolved in 1.0L solution
Molarity = 11.45M
In terms of significant figures- the answer should be : Molarity = 11M - correct to 2 significant figures.
1 Litre of the solution has mass = 1.10×1L=1.10g
Now,1.10g of the solution contains 1.10×30℅ H2so4. =0.418g
0.418g= 0.418/98 =0.004 mole h2so4
Now,we know that molarity of a solution is the number of moles of solute present in 1 litre of the solution.
Therefore,molarity is 0.004M
hope,i helped