A cone is made by rolling up a sector of central angle 144º.What is the ratio between the radius and slant height of the cone?
Share
A cone is made by rolling up a sector of central angle 144º.What is the ratio between the radius and slant height of the cone?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
[tex]\bf{Answer:-}[/tex]
Curved surface area of cone = πrl
πrl = 108 × 22/7
πrl = 339.4285714
Now Area of sector formed = CSA of cone
theta/ 360 ×πr^2 = πrl
120/360 × 22/7 ×r^2 = 339.4285714
r^2 = 324
r = 18 ------> 1
Now put the value of r in
rl = 108
18 ×l = 108
l = 6 -----> 2
So the ratio of radius is to slant height that is r : l = 3 : 1.
Answer:
Curved surface area of cone = πrl
Curved surface area of cone = πrlπrl = 108 × 22/7
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of cone
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714r^2 = 324
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714r^2 = 324r = 18 ------> 1
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714r^2 = 324r = 18 ------> 1Now put the value of r in
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714r^2 = 324r = 18 ------> 1Now put the value of r inrl = 108
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714r^2 = 324r = 18 ------> 1Now put the value of r inrl = 10818 ×l = 108
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714r^2 = 324r = 18 ------> 1Now put the value of r inrl = 10818 ×l = 108l = 6 -----> 2
Curved surface area of cone = πrlπrl = 108 × 22/7πrl = 339.4285714Now Area of sector formed = CSA of conetheta/ 360 ×πr^2 = πrl120/360 × 22/7 ×r^2 = 339.4285714r^2 = 324r = 18 ------> 1Now put the value of r inrl = 10818 ×l = 108l = 6 -----> 2So the ratio of radius is to slant height that is r : l = 3 : 1.