A container has mixture of three liquids, A, B and C in ratio of 2:3:5. From this container 4 litre of liquid has been taken out and replaced with 2 litre A and 2 litre C. after this, the ratio of liquids in container becomes 23:27:50. What was the initial amount of B in container? a) 12 litre b) 8 litre c) 15 litre d) 20 litre
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Step-by-step explanation:
26z’ liters and ‘29z’ liters, respectively
So, 25x = 79z + 10
And 25x - 50z = y
⇒ y + 50z = 25x
⇒ y + 50z = 79z + 10
⇒ y = 29z + 10
⇒ 29z = y - 10
Also, 29z = (12y / 25) + 146
⇒ y - 10 = (12y / 25) + 146
⇒ 13y / 25 = 156
⇒ y = 300
So, 300 = 29z + 10; z = 10
∴ 25x = 790 + 10
⇒ x = 32
So, the amount of liquid B initially in the container = 32 × 13 = 416 liters
∴ the required value is 416 liters