a copper wire has 1x10^29 free electrons per cubic meter and a cross-sectional area of 2 mm^2 carries a current of 6A. Calculate the force acting on each electron if the wire is now placed in a uniform field of flux density of 0.1t perpendicularly
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Answer:
The current in a conductor is given by
i=nqAv
where v is drift velocity, A is cross sectional area and n is number of free electrons
v=
nqA
i
Force on each electronF=qvB
=q
nqA
i
B
=
nA
Bi
=
10
29
×3×10
−6
0.15×4
=20×10
−25
N
Explanation:
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