a cylinder kal roller of length 2.5 M and diameter 3M when rolled on a road was found to cover the area of 33000 M sq how many revolutions did it make
a cylinder kal roller of length 2.5 M and diameter 3M when rolled on a road was found to cover the area of 33000 M sq how many revolutions did it make
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Hi there !!
The length of the cylindrical pipe is the same as its height.
h = 2.5 m
r = 1.75 m
Total area covered = 5500 m²
Area covered by 1 revolution = C.S.A of the pipe
= 2πrh
= 2 × 22/7 × 1.75 × 2.5
= 27.5 m²
No : of revolutions made = Total area covered ÷ C.S.A
= 5500 ÷ 27.5
= 200 revolutions
r,=1 .75
total area equal to 5500 m square
area of one revolution=C.S .Aof the pipe
=2πrh
=2×22/7×1.75*2.5
=27.5m²
the revolution did it make
5500/27.5=200revolution