a cylindrical copper rod has a resistance of 10 ohm the rod is reformed to twice its original length without any change in volume calculate the resistance of newly formed cylinder
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a cylindrical copper rod has a resistance of 10 ohm the rod is reformed to twice its original length without any change in volume calculate the resistance of newly formed cylinder
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Answer:
Volume
=
π
r
2
L
=
A
×
L
L
′
=
2
L
⟹
A
′
=
A
2
Since volume is constant.
We know,
R
=
ρ
×
L
A
Hence,
R
′
R
=
L
′
L
×
A
A
′
=
2
L
L
×
A
A
2
=
4
Hence,
R
′
=
4
R