A diatomic molecule having a dipole moment of 1.92D and bond length of 2 A. Its percentage ionic character is
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A diatomic molecule having a dipole moment of 1.92D and bond length of 2 A. Its percentage ionic character is
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Answer:
dipole moment = q x d
= 4.8 × 10 ^ (-10) esu x 2 x 10^ (-8) cm
9.8 x 10^(-18) esu.cm = 9.8 D
% ionic character is = 1.92 D x 100
-------------- =19.5%
9.8D