A door of length 2m and breadth 1 m and a sqbtuare window of dimension 0.3m is fitted in a wall. The length of the wall is 4.5m and thbuie Breadth is 3.6m. find the cost of whitewashing of the wall, at ev7 the rate of ₹20 sq.m
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A door of length 2m and breadth 1 m and a sqbtuare window of dimension 0.3m is fitted in a wall. The length of the wall is 4.5m and thbuie Breadth is 3.6m. find the cost of whitewashing of the wall, at ev7 the rate of ₹20 sq.m
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Step-by-step explanation:
Length of wall= 4.5m
Breadth of the wall= 3.6m
Length of the door =2m
Breadth of the door= 1m
Area of the wall = l\times b=4.5m\times3.6m=\ 16.20m^2l×b=4.5m×3.6m= 16.20m
2
Area of the door = l\times b=2m\times1m=2m^2l×b=2m×1m=2m
2
Therefore area of the wall to be white washed= Area of the wall - Area of the door
=Rs\ 14.20\times20=Rs\ 284.00=Rs 14.20×20=Rs 284.00
Hence, the required area= 14.20m^214.20m
2
and the required cost= Rs 284
Answer:
282.2
Step-by-step explanation:
Lenght of door=2m
Breadth of a door=1m
Area of the door=2sq.m
l×b=Area
2×1=2sq.m
2sq.m
Side of a square window=0.3m
Area if a square window=
S×S=Area
0.3×0.3=0.09sq.m
Total area of the wall that do not need to be whitewashed=
2sq.m+0.09sq.m
2.09sq.m
Length of the wall=4.5m
Breadth of the wall=3.6m
Area of the wall=16.2sq.m
l×b=Area
4.5×3.6=16.2sq.m
Total area of the wall that needs to be painted=
16.2sq.m-2.09sq.m
14.11sq.m
Cost of white washing 1sq.m=20
Cost of white washing 14.11sq.m=282.2