A family of 12 buys 30 kg of sugar which lasts for 20 days
. If they buy
40 kg and it lasts for only 8 days, find the increase in the number of family
members
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A family of 12 buys 30 kg of sugar which lasts for 20 days
. If they buy
40 kg and it lasts for only 8 days, find the increase in the number of family
members
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Answer:
Question:
A family of 12 buys 30 kg of sugar which lasts for 20 days. If they buy 40 kg and it lasts for only 8 days, find the increase in the number of family members.
Solution :
In First Case:
A family of 12 Menbers buys 30 kg of sugar which lasts for 20 days. (given)
ATQ: Men : 12
Time : 20days
Work done according to question : 30
In Second Case:
A family of ? members buys 40 kg of sugar which lasts for 8 days
ATQ: Men : x
Time : 8 days
Work done according to question : 40
According to Maths Formula
\begin{gathered}= \frac{men \times time}{work \: done} \\ \frac{12 \times 20}{30} = \frac{x \times 8}{40} \\ \frac{12 \times 20 \times 40}{30 \times 8} = x \\ 40 = x \\ x = 40 \\\end{gathered}
=
workdone
men×time
30
12×20
=
40
x×8
30×8
12×20×40
=x
40=x
x=40
In First Case, family members = 12
Second Case, family members = 40
Therefore, Increase in the number of family members in Second Case is 28(40-12).
Step-by-step explanation:
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