A farmer had fodder for 40 animals for 60 days. He bought some more animals and the forder lasted for 50 days. How many animals did he buy?
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A farmer had fodder for 40 animals for 60 days. He bought some more animals and the forder lasted for 50 days. How many animals did he buy?
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Verified answer
Given:-
To Find:-
Answer:-
⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question
It is given that the fodder for 40 animals was lasted for 60 days .
We have to calculate the no. of animals he had brought in which the fodder lasted for 50 days . So,
Let the total animals in 2nd case be x
40/50 = x/60
50 × x = 60 × 40 (direct variation)
x = 2400/50
x = 48
when farmer had 40 animals the fodder was lasted for 60 days .
If farmer had 48 animals the fodder lasted for 50 days.
So , the Number of animals brought by the farmer = 48-40
Number of animals brought by the farmer = 8
Given:-
To Find:-
Solution:-
Let the total no. of animals be x.
Then, simply the equation formed is:-
On Cross Multiplication,
Total no. of animals = 48
And,
No. of animals bought = 48 - 40 = 8
Hence, 8 animals are bought by the farmers.
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